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Regression to the mean

The best guess for a retest lies between the first score and the average, so extreme performers drift back with no cause at all.

Helps to know firstLinear regression

Helps to know first
This topic

First, the picture

A thousand students take two tests. Light up the top tenth on the first, and watch where they land on the second.

Regression to the mean

1000 students sit two tests; the best tenth on the first is followed to the second (seed 9200).

The top tenth on test 1 is lit: on average 662.8, far above the mean of 500. Now the same students sit test 2.

correlation
0.60
lit group, test 1
662.8
lit group, test 2
–

Predict first. On test 2, where will the lit group be on average?

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Describe this picture

Three panels that stay apart. The first, “the population”, describes the scores: both tests have mean 500 and standard deviation 100, with correlation 0.6 between them. The second, “the students”, shows 1000 seeded students (seed 9200) as dots, test 1 across and test 2 up, with the top tenth on test 1 lit. The third, “the lit group”, shows the lit students’ scores as dots on one axis from 300 to 900, with a dashed line at the average, 500, and a bar at the group’s test-1 mean, 662.8. Before the clip a question asks where the lit group will be on test 2, on average: as high as before, about halfway back to the average, or back at the average. A tap picks one and starts the clip. In the clip, over 8 seconds, the lit dots slide from their test-1 scores to their test-2 scores and end lower on average; a second bar marks the test-2 mean, 588.9, and your guess is a dotted bar. Readouts give the correlation and the two means. After the clip a slider sets the correlation from 0 to 1 in steps of 0.05, using the same underlying draws.

The top tenth fall back

Before the clip you guessed. The top tenth on test 1 average about 675 there; on test 2 the same students average about 605, well above 500 but well below where they were. They fell back partway, and nothing was done to them. The clip’s 1000 students came out a little lower on both, 662.8 and 588.9, with the same fall back.

Here is why. A test score is partly lasting skill and partly the luck of the day. The top tenth on test 1 are mostly skilled people who also had a good day. On test 2 their skill stays, but their luck is new, and on average ordinary. So they come back towards the middle. This drift is called regression to the mean.

Watch out

A fall after an extreme first result does not need a cause. Fatigue, complacency or a treatment may be blamed, or praised, for what chance alone would do.

The line in standard units

Put both scores in standard units, ZX=(X−μX)/σXZ_X=(X-\mu_X)/\sigma_X and ZY=(Y−μY)/σYZ_Y=(Y-\mu_Y)/\sigma_Y, each with mean 0 and standard deviation 1. The regression line of Linear regression then has slope ρXY\rho_{XY}, the correlation, and passes through the origin:

E{ZY∣ZX=z}=ρXY z.\mathbb{E}\{Z_Y\mid Z_X=z\}=\rho_{XY}\,z.

For bell-shaped scores the retests of people with first score zz also scatter, with standard deviation 1−ρXY2\sqrt{1-\rho_{XY}^2}.

Since ρXY\rho_{XY} is less than 1, the predicted retest is always nearer the mean than the first score: a student 2 standard deviations up is expected 2ρXY2\rho_{XY} up next time. After the clip, drag the correlation. At 1 nobody moves: the second test repeats the first. At 0 the lit group falls all the way back to 500: the first test told nothing about the second.

The top tenth in numbers. The top tenth of a standard bell starts at z0.90=1.2816z_{0.90}=1.2816, and its mean is the bell’s height there over 0.1: fZ(1.2816)/0.1=1.7550f_Z(1.2816)/0.1=1.7550. So their first-test mean is 500+100×1.7550=675.50500+100\times1.7550=675.50, and their expected retest mean is 500+175.50 ρXY500+175.50\,\rho_{XY}: about 553 at ρXY=0.3\rho_{XY}=0.3, 605.30 at 0.6, about 658 at 0.9.

From test 2 back to test 1

If the fall back were caused by time, by practice or tiredness, it would only run forwards. It runs both ways.

It runs both ways

The same 1000 students; now the best tenth on test 2, followed back to test 1.

Now light the top tenth on test 2 instead: on average 662.1. Where were they on test 1?

lit group, test 2
662.1
lit group, test 1
–
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Describe this picture

The same 1000 students, now with the top tenth on test 2 lit, as dots on one axis from 300 to 900 with a bar at their test-2 mean, 662.1. In the clip the dots slide back to their test-1 scores, and a second bar marks the group’s test-1 mean, 589.1: lower than its test-2 mean. Readouts give both means. The panel has a play button and no other control.

The top scorers on test 2 also scored lower, on average, on test 1. By symmetry, by the same amount. The drift is a property of picking extremes on a noisy measure, not of anything that happened between the tests.

Regression and treatments

Blood pressure readings have mean 130 and standard deviation 15 in a population, and two readings of the same person correlate at ρXY=0.7\rho_{XY}=0.7. Patients whose first reading was 160, two standard deviations up, are expected at 130+0.7×2×15=151130+0.7\times2\times15=151 on the next reading: a fall of 9 with no treatment at all.

Give those patients a pill between the readings, and the pill will seem to work. The only fair comparison is a control group: equally extreme patients, chosen the same way, who do not get the pill. Their fall measures regression to the mean, and only the extra fall in the treated group is the pill’s.

The regression line and the SD line

In standard units, the line through the cloud’s long axis, the SD line, has slope 1: it moves one standard deviation in yy for each one in xx. The regression line has slope ρXY\rho_{XY}, flatter. The SD line looks like the natural fit, but predicting from it overestimates every extreme case: it ignores the luck that will not repeat.

Worked example

1. Retests. Scores have mean 100, standard deviation 15 and ρXY=0.6\rho_{XY}=0.6. A first score of 130 (z=2z=2) predicts a retest of 100+0.6×2×15=118100+0.6\times2\times15=118, with spread 151−0.36=1215\sqrt{1-0.36}=12; so 95 % of such retests lie within about 118±23.5118\pm23.5. A first score of 70 predicts 82.

2. The top tenth. First-test mean 675.50; retest means 500+175.50 ρXY500+175.50\,\rho_{XY}: 500 at ρXY=0\rho_{XY}=0, 605.30 at 0.6, 675.50 at 1.

3. Blood pressure. First reading 160, expected second reading 151, with no treatment.

4. Two lines. With equal spreads and ρXY=0.6\rho_{XY}=0.6, the SD line has slope 1 and the regression line 0.6.

Try it yourself. A first zz of −1.5-1.5 with ρXY=0.5\rho_{XY}=0.5 predicts a retest zz of −0.75-0.75. If you pick the bottom tenth, their average rises on retest. With ρXY=1\rho_{XY}=1, every score repeats exactly.

Where you’ll meet this

Sport. The “rookie of the year” who disappoints in the second season, and the team that slumps after a record year, are often regression to the mean: the best first seasons had the most luck in them.

Schools and tests. Schools picked for help because of a bad year often improve the next, help or no help. Only a comparison with similar schools that got no help shows what the help did.

Road safety. Speed cameras placed at sites with many crashes last year are followed by fewer crashes, partly because last year was unusually bad.

Measurements. An extreme sensor reading is partly noise, so the best estimate of the true value lies nearer the average: the idea behind the shrinkage of Estimators: bias and variance and the posterior mean of Priors, posteriors and credible intervals.

Where this leads · a shorter projection

In standard units the correlation is the cosine of the angle between the two centred data vectors. Projecting one onto the other’s direction shortens it by that cosine: the fall back is the projection’s shortening. Projections and Length and the dot product in the linear algebra course show it.

Reference card

QuantityFormulaNotes
Standard unitsZX=(X−μX)/σXZ_X=(X-\mu_X)/\sigma_Xmean 0, SD 1
Predicted retestE{ZY∣ZX=z}=ρXYz\mathbb{E}\{Z_Y\mid Z_X=z\}=\rho_{XY}znearer the mean
Spread of retests1−ρXY2\sqrt{1-\rho_{XY}^2} in standard unitsbell-shaped scores
Raw unitsslope ρXY σY/σX\rho_{XY}\,\sigma_Y/\sigma_Xthe SD line: σY/σX\sigma_Y/\sigma_X
Top tenth of a bellmean fZ(1.2816)/0.1=1.7550f_Z(1.2816)/0.1=1.7550retest 1.7550 ρXY1.7550\,\rho_{XY}
Symmetric in timetop on test 2 were lower on test 1no cause needed
Fair test of a treatmentan equally extreme control group

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